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In this last section of this chapter we have to look at some applications of exponential & logarithm functions.
Compound Interest
This first application is compounding interest & there are in fact two separate formulas which we'll be looking at here. Let's get first those out of the way.
If we were to put P dollars in an account which earns interest at a rate of r (written as a decimal) for t years (yes, it have to be years) then,
1. if interest is compounded m times per year we will have t m
A = P (1 + (r /m)tm
dollars after t years.
2. if interest is compounded continuously then we will have
A = Pert
y2/3(y4/3\y1/3
5(4a+1)+6=-(-11a+1)+6a
x2 -x = 7 -3 -5 1 5 -3
330 radians
76 * 10 -9
x plus 6 equal -10
Paula weighs 110 pounds, and Donna weighs p pounds. Paula weighs more than Donna. Which expression shows the difference in their weights?
find the number of hours it would take to drive 168 miles at an average rate of 48 miles an hour. use the formula d=rt
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(b+a)+[-(a+0+b)]=0
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