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At what angle should a body be projected with a given velocity 24m/s just to pass over the obstacle 14m high at a given distance of 24m.
Solution: 14=24xtan(θ)-(g*)(242)/(2*242cos2( θ ))
Two point changes q1 and q2 are placed at a distance r from one another then electrostatic potential energy of two phase charge system will be kq 1 q 2 /r . We take P.E. of two ch
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