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AND: Logical AND: This instruction bit by bit ANDs the source operand that might be an immediate, or a memory location or register to the destination operand that might be a memory location or register. The result is in the destination operand. At least 1 operand should be a register or a memory operand. Both of the operands can't be memory locations or immediate operands. An immediate operand can't be a destination operand. The instance of this instruction is as follows:
Example :
If the content of register AX is 3FOFH, the first instance instruction will carry out the operation as given below. The result 3F9FH will be in the AX register.
The result 0008H will be in register AX.
CMP: Compare: - This instruction compares the source operand, which can be a register or memory location an immediate data with a destination operand that might be a register or a
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Internal Architecture of Microprocessor : The architecture of 8086 provides a number of improvements over 8085 architecture. It supports a, a set of 16-bit registers ,16-bit AL
Pin functions for the minimum mode operation of 8086 are following: 1) M/I/O -Memory/IO: This is a status line logically equivalent to S2 in maximum mode. When it is low, it
Write a program that will input a number from the keyboard, and then display the number in binary form, as well as the number of one's in the number. Hint: Shift the value left (or
do you type assembly code or machine code instructions like b8 0100000 to add to register EAX straigt onto dos command line or do you have to same in a file and what extension woul
Program : A program to move a string of the data words from offset 2000H to offset 3000H the length of the string is OFH. Solution : For writing this program, we will use
Queue Operation : RQ/CT0, RQ/G1-Request/Grant: These pins are utilized by other local bus masters, in themaximum mode, to force the processor to release the loca
General Bus Operation The 8086 has a joined data and address bus commonly referred to as a time multiplexed address and data bus. The major reason behind multiplexing address
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
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