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1. Produce a figure with an appropriate figure legend of your SDS-PAGE gel that could be published in a scientific journal.
2. Fill in the table to report your calculated estimates for the molecular masses (kDa) of the proteins in the milk sample. You can enter up to 3 different significant bands that you observed in the respective fractions.
Protein fraction
Estimated molecular mass (kDa)
Casein proteins
Whey proteins
Small molecular mass proteins
3. Draw a graph of absorbance against fraction number for the gel filtration chromatography. Using Excel you will need to create a graph with two axes (one axis on the left for the absorbance of haemoglobin (Abs 400 nm) and one axis on the right for the absorbance of vitamin B12 (Abs 550 nm).
4. Explain in molecular terms the observed movement of the various sized proteins through:
a) the polyacrylamide gel
b) the gel filtration column
5. A cell consists of thousands of individual molecular components. To understand biochemical pathways is often necessary to separate, purify and analyse the molecular constituents of a cell. Name three different biochemical/biophysical properties in which biological molecules differ from each other and think about a corresponding technique that can be exploited to separate and/orcharacterize such metabolites.
Biochemical/Biophysical property
Technique that exploits this property
Example given: different ionic charge
Example given: separation on gel in electric field
6. Consider an individual who had to dash for 500 metres in order to catch a tram that was just about to depart. Indicate thelikely concentration of metabolites that molecular analysis would reveal in the muscle tissue of this person. Increased, decreased and unchanged are describing levels relative to a healthy resting state.
Metabolite
Concentration
(Increased, decreased or unchanged)
acetyl-CoA
pyruvate
lactate
glucose (blood)
glucose-6-phosphate
EtOH
glyceraldehyde-3-phosphate
AMP
glucose-1-phosphate
ephinephrine
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The radius of the nucleus is related to the mass number A by : (1 )R= R 0 A 1/2 (2) R= R 0 A (3) R= R 0 A 2
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The Basicity is 3 as there are 3 H atoms that can be displaced from compound.
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