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The third line in Balmer series corresponds to an electronic transition between which Bohr's orbits in hydrogen:
(1) 5 → 3
(2) 5 → 2
(3) 4→ 3
(4) 4 → 2
Ans: 5 → 2
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The electronic configuration of an element is 1s 2 , 2s 2 2p 6 3s 2 3p 6 3d 5 4s 1 . This represents its: (1) Excited state (2) Ground state (3)Cationic for
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What does the HA and A- stand for in buffer solution equations? Ka=HA/A-
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