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The third line in Balmer series corresponds to an electronic transition between which Bohr's orbits in hydrogen:
(1) 5 → 3
(2) 5 → 2
(3) 4→ 3
(4) 4 → 2
Ans: 5 → 2
NaCl
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The expression for Bohr's radius of an atom is: (1) r= n 2 h 2 / 4 Π 2 me 4 z 2 (2) r= n 2 h 2 / 4 Π me 2 z 2 (3) r= n2h2/4 Π me 3
Chloride of metal is MCl 2 . The formula of its phosphate will be: (1) M 2 PO 4 (2) M 3 (Po 4 ) 2 (3) M 2 (
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