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The third line in Balmer series corresponds to an electronic transition between which Bohr's orbits in hydrogen:
(1) 5 → 3
(2) 5 → 2
(3) 4→ 3
(4) 4 → 2
Ans: 5 → 2
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Q. Simple molecular orbital description? we can give a simple molecular orbital description of bonding in B 2 H 6 as follows. Each boron atom is sp 3 hybrid giving four sp 3
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