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The third line in Balmer series corresponds to an electronic transition between which Bohr's orbits in hydrogen:
(1) 5 → 3
(2) 5 → 2
(3) 4→ 3
(4) 4 → 2
Ans: 5 → 2
The total number of orbitals in an energy level designated by principal quantum number n is equal to: (1) 2n (2) 2n 2 (3) n
how do you calculate the mass atomic number of an element?
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