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In the amortized analysis, the time needed to perform a set of operations is the average of all operations performed. Amortized analysis considers as a long sequence of operations rather than just one and then gives a worst-case estimate. There are three different methods by which the amortized cost can be calculated and can be differentiated from the actual cost. The three methods are following:
Aggregate analysis: It determines the average cost of each operation. i.e., T(n)/n.
The amortized cost is similar for all operations. Accounting method: The amortized cost is distinct for all operations & charges a credit as prepaid credit on some of the operations.
Potential method: It also has distinct amortized cost for each of operation and charges a credit as the potential energy to other operations.
There are special operations like stack operations (push, pop, multipop) and an increment that can be considered as instance to verify the above three methods.
Every operation over a splay tree and all splay tree operations take O(log n) amortized time.
adjacency multilist
Write an algorithm by using pseudocode which: Inputs top speeds of 5000 cars Outputs fastest speed and the slowest speed Outputs average speed of all the 5000 cars
explain working of siso-register to store 1011 and show timing diagram &table
Define the term counting - Pseudocode Counting in 1s is quite simple; use of statement count = count + 1 would enable counting to be done (for example in controlling a repeat
Q. Explain quick sort? Sort the given array using quick sort method. 24 56 47 35 10 90 82 31
Write an algorithm for compound interest.
The most common way to insert nodes to a general tree is to first discover the desired parent of the node you desire to insert, and then insert the node to the parent's child list.
The Space - Time Trade Off The best algorithm to solve a given problem is one that needs less space in memory and takes less time to complete its implementation. But in practic
In the last subsection, we have implemented a stack by using an array. While a stack is implemented by using arrays, it suffers from the basic restriction of an array - i.e., its s
Insertion: Records has to be inserted at the place dictated by the sequence of keys. As is obvious, direct insertions into the main data file would lead to frequent rebuilding of
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