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Find out the greater of two consecutive positive odd integers whose product is 143. Let x = the lesser odd integer and let x + 2 = the greater odd integer. Because product is a
((1/x^1/2-(x-1)^1/2)+(1/(5-3(x-1)^2)^1/2)
v=u+at s=ut+1/2at^2
Determine the general solution to 2t 2 y'' + ty' - 3y = 0 It given that y (t) = t -1 is a solution. Solution Reduction of order needs that a solution already be iden
Taking 2^x=m and solving the quadratic for getting D>=0 we get range= [3/4 , infinity )
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3.6Find the general solution of the differential equation Y" + 4y = Sec2 2x
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If y 1 (t) and y 2 (t) are two solutions to y′′ + p (t ) y′ + q (t ) y = 0 So the Wronskian of the two solutions is, W(y 1 ,y 2 )(t) = =
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