Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Q. What are the advantages of an RC coupling over a direct coupling? Draw a basic Rc coupling network and explain.
Figure -RC-coupled transistor amplifier
The network of R1, R2, and C1 enclosed in the dashed lines of the figure is the coupling networkR1 acts as a load resistor for Q1 (the first stage) and develops the output signal of that stage The capacitor, C1, "blocks" the dc of Q1's collector, but "passes" the ac output signal. R2 develops this passed, or coupled, signal as the input signal to Q2 (the second stage). This arrangement allows the coupling of the signal while it isolates the biasing of each stage. This solves many of the problems associated with direct coupling. RC coupling does have a few disadvantages. The resistors use dc power and so the amplifier has low efficiency. The capacitor tends to limit the low-frequency response of the amplifier and the amplifying device itself limits the high-frequency response. For audio amplifiers this is usually not a problem; techniques for overcoming these frequency limitations will be covered later in this module. The direct-coupled amplifier is not very efficient and the losses increase as the number of stages increase. Because of the disadvantages, direct coupling is not used very often.
This explains why the low frequencies are limited by the capacitor. As frequency decreases, XC increases. This causes more of the signal to be "lost" in the capacitor. The formula for XC also shows that the value of capacitance (C) should be relatively high so that capacitive reactance (XC) can be kept as low as possible. So, when a capacitor is used as a coupling element, the capacitance should be relatively high so that it will couple the entire signal well and not reduce or distort the signal
need help on 2330 level 2 motors assignment
Q. The energy stored in a 2-µF capacitor is given by w c (t) = 9e -2t µJ for t ≥ 0. Find the capacitor voltage and current at t = 1s.
Q. (a) Consider the amplifier block in the circuit configuration of Figure. Find an expression for v 2 /v 1 in terms of R i , R o , and A of the amplifier. (b) Determine the
Norton's theorem procedure: 1. Remove R L from the circuit. Search I N by shorting links output terminal. 2. Search R N by short-circuit voltage source or open-circuit
principle of 120 degree mode of operation of voltage source intverter
1) Use plot of the stock return and consider the Autocorrelation Function to determine the auto-regressive structure of the data and explain why you think the return is stationary
Describe the three main sources of power dissipation in CMOS logic. Hence calculate the power dissipated in a CMOS ASIC of 40,000 gates operating at a frequency of 133MHz with a s
how to write theory background on practical about this topic.
Define addressing modes of 8085. a) Immediate addressing b) Register addressing c) Direct addressing d) Indirect addressing e) Implicit addressing
Diffusion Current : The carrier currents are also due to concentration gradients in the doped material which lead to diffusion of carriers from high concentration region to l
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd