addition, Mathematics

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Write following in terms of simpler logarithms, Write following in terms of...

Write following in terms of simpler logarithms.  (a) log 3 (9 x 4    / √y) Solution log 3 (9 x 4 / √y) =log ­ 3 9x 4 -  log  y (1/2) =log ­ 3 9 + log ­ 3 x 4

Solution to a differential equation, A solution to a differential equation ...

A solution to a differential equation at an interval α Illustration 1:   Show that y(x) = x -3/2 is a solution to 4x 2 y′′ + 12xy′ + 3 y = 0 for x > 0. Solution : We'll

Universal set, Universal set The term refers to the set which contains...

Universal set The term refers to the set which contains all the elements such an analyst wishes to study.  The notation U or ξ is usually used to denote universal sets.

Exponential and geometric model, Exponential and Geometric Model Expo...

Exponential and Geometric Model Exponential model  y = ab x Take log of both sides log y = log a + log b x log y = log a + xlog b Assume log y = Y and log a

Interpretations of definite integral, Interpretations of Definite Integral ...

Interpretations of Definite Integral There are some quick interpretations of the definite integral which we can give here. Firstly, one possible interpretation of the defini

????????, ?????? ?????? ?? ???? ??????? ???????? ?????? 3.5 ?? ??? ???? ???...

?????? ?????? ?? ???? ??????? ???????? ?????? 3.5 ?? ??? ???? ???? ????? 50??/???? ??????20??/???? ???? ?? ?? ?????? ???????? ??? ??? ?? ??????? ??????? ? ?? ????? ????

Theorem of continuous functions, Consider the subsequent IVP. y' = f(t,y...

Consider the subsequent IVP. y' = f(t,y) ,        y(t 0 ) = y 0 If f(t,y) and ∂f/∂y are continuous functions in several rectangle a o - h o + h which is included in a

Engg maths, How to get assignment to solve and earn money

How to get assignment to solve and earn money

Derive the hicksian demand function using indirect utility , (a) Derive the...

(a) Derive the Marshalian demand functions and the indirect utility function for the following utility function: u(x1, x2, x3) = x1 1/6 x2 1/6 x3 1/6    x1≥ 0, x2≥0,x3≥ 0

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