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Devise one activity each to help the child understand 'as many as' and 'one-to-one correspondence'. Try them out on a child/children in your neighbourhood, and record your observations.So far we have considered some examples of activities that you can devise to introduce and strengthen the concepts of classification, ordering and one-to-one correspondence. Here we would like to mention a point of caution! While organising such activities, it is important to be careful when setting them up. This is because we may inadvertently mislead the child as in the following example :
When talking about 'as long as', Dolly's teacher always used a rod for comparing with. Because of this, Dolly thought that the rod and 'as long as' are somehow related, and that 'as long as' can only be applied to that kind of rod.
Thus, while introducing a concept, we should devise as many different activities as possible with a variety of materials, so that children can correctly glean the concept and generalise it. For example, let childrenencounter the term 'as long as' with reference to sticks, pencils, ribbons, spoons, blocks, ropes, in a variety of situations. Then, from these various experiences they will be able to draw out the meaning of 'as long as'. + Another point that we must keep in mind is that a child may not be able to perform a task simply because of language incompetence, and not cognitive incompetence. You can think of an example to illustrate this while doing the following exercises.
an insurance salesman sells policies to 5 men, all of identical age in good health. the probability that a man of this particular age will be alive 30 years hence is 2/3.Find the p
Q. Assume a birthday is equally likely to occur in each of the 365 days. In a group of 30 people, what is the probability that no two have birthdays on the same day? Solution:
A car travels 283 1/km in 4 2/3 hours .How far does it go in 1 hour?
Provide the vector for each of the following. (a) The vector from (2, -7, 0) - (1, - 3, - 5 ) (b) The vector from (1,-3,-5) - (2, - 7, 0) (c) The position vector for ( -
Solve following x - x e 5 x + 2 = 0 . Solution : The primary step is to factor an x out of both terms. DO NOT DIVIDE AN x FROM BOTH TERMS!!!! Note as well that it i
Tangent, Normal and Binormal Vectors In this part we want to look at an application of derivatives for vector functions. In fact, there are a couple of applications, but they
Before taking up division of polynomials, let us acquaint ourselves with some basics. Suppose we are asked to divide 16 by 2. We know that on dividing 16 by
(a) Given a norm jj jj on Rn, express the closed ball in Rn of radius r with center c as a set. (b) Given a set A and a vector v, all contained in Rn, express the translate of A by
what does 4/100+1/10=
Approximating solutions to equations : In this section we will look at a method for approximating solutions to equations. We all know that equations have to be solved on occasion
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