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In the earlier section we solved equations which contained absolute values. In this section we desire to look at inequalities which contain absolute values. We will have to examine two separate cases.
Inequalities Involving < and ≤
As we did with equations let's begin by looking at a fairly simple case.
p ≤ 4
This says that no matter what p is it ought to have a distance of no more than 4 from the origin. It means that p have to be somewhere in the range,
-4 ≤ p ≤ 4
We could have alike inequality with the < and obtain a similar result.
Generally we have the following formulas to use here,
If |p| ≤ b, b = 0 then - b ≤ p ≤ b
If |p| < b, b =0 then - b < p < b
graph leftmost point and 3 additional points f(x)=vx+3
An office contains two envelope stuffing machines. Machine A can stuff a batch of envelopes within 5 hours, whereas Machine B can stuff batch of envelopes within 3 hours. How much
f(x)=x^2+6x+5 given f(2)
Synthetic division table In a synthetic division table perform the multiplications in our head & drop the middle row only writing down the third row and as we will be going thr
2x-3(2x+7)=-13
Determine which system below will produce infinitely many solutions. 2x + 5y = 24 2x + 5y = 42 3x - 2y = 15 6x + 5y = 11 4x - 3y = 9 -8x + 6y = -18 5x - 3y = 16 -2x + 3y =
Express the answer as an integer, simplified fraction, or a decimal rounded to two decimal places.
2-1-f+7=
4+3/5
-6k+7k=
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