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1-Phase Full Bridge inverter will RL Load
For a resistive load R the load current wave form will be identical with load voltage wave form and feedback diodes will not come into conduction. In the case of RL -Load the wave form of output current is shown in the circuit of 1-? full bridge inverter with Rl load is shown .
Before t =0 thyristors T3 and T4 are conducting and load current is flowing in negative direction. After T3 and T4 are turned of at t=0 load current io can not change its direction immediately due to the existence of inductance in the load. Therefore after t= 0 diodes D1 and D2 start conducting and allow the load current to flow against the source voltage. Load voltage becomes Vdc.
At t=0 thyristor T1 and T2 are gated but these thyristors will not turn on because these are reverse biased by voltage drops across D1 and D2. After the load current becomes equal to zero T1 and T2 start concocting up to the period t = T/2 now load current start flowing in positive direction ( as we assumed in circuit) at t= T/2 T1 and T2 are commutated and T3 and T4 are gated but tagging the current can not change its direction immediately. As a result diodes D3 and D4 starts conducting to allow the current to flow in positive direction. Thyristors T3 and T4 will not start conduction until the load current through diodes D3 and D4 falls to zero because these thyristors will not turn on as these are reverse biased by the voltage drops in the D3 and
I need help with some circuits.
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