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If roots of (x-p)(x-q) = c are a and b what will be the roots of (x-a)(x-b) = -c please explain? Ans) (x-p)(x-q)=c x2-(p+q)x-c=0 hence, a+b=p+q and a.b=pq-c
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2-3+=3+-4
Find the coordinates of the point P which is three -fourth of the way from A (3, 1) to B (-2, 5).
Solve the subsequent IVP and find the interval of validity for the solution xyy' + 4x 2 + y 2 = 0, y(2) = -7, x > 0 Solution: Let's first divide on both
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Taking 2^x=m and solving the quadratic for getting D>=0 we get range= [3/4 , infinity )
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