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You conducted a Chi-Square Goodness of Fit Test in your ASCI 691 capstone project. Unfortunately, you did not get the sample size you had hoped for during your research. You were able to get 55 in the sample. Calculate your actual power (post hoc). You did a 2 X 2 table. Assume you had a medium effect size. How did I arrive at my conclusion?
If demand is normally distributed, a basic EOQ is appropriate. a single-period model could not be appropriate. we should produce to fill demand, rather than filling it through orders.
question letnbspomega be a space of results and b one happening such that probability of b gt 0 pb gt 0. prove that
State the null hypothesis and the alternate hypothesis. State the significance level. State the decision rule. Give the formula for the test statistic.
Findout the margin of error for this survey if we want a 99 percent confidence in our estimate of the percent of adults over 50 who take vitamin supplements.
A recent article in Vitality magazine reported that the mean amount of leisure time per week for American men is 40.0 hours. You believe this figure is too large and decide to conduct your own test.
A random sample of 48 managers of large hotels has mean X‾= 5.91. The null hypothesis for the researcher's test is?
Where Z~N(0,1). Also let [empty set symbol] denote the standard normal density function. Show that, d/dx [empty set symbol] (- square root of x) = -1/2 x^-1/2 [empty set symbol] (-square root of x).
if ho b1 0 is not rejected what is the best estimate for the value of the response variable for any value of the
A survey is being planned to determine the mean amount of time corporation executives watch television. A pilot survey indicated that the mean time per week is 20 hours, with a standard deviation of 5.5 hours
the cost of a college education has increased at a much faster rate than costs in general over the past twenty years.
Is there a difference in the extent of wound healing by treatment? (Hint: Are treatment and the percent wound healing independent?) Run the appropriate test at a 5% level of significance.
Calculate the test statistic for testing the null hypothesis. The slass mean will be not be signfically different from the population mean. What is your decision about the null hypothesis?"
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