Write the net ionic equation for the reaction

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Question:

A 0.879g of a sample a CaCl2*H20/K2C2O2 solid salt mixture is dissolved in 150mL of deionized water. A precipitate forms which is then filtered and dried. The mass of this precipitate is 0.284g. The limiting reagent in the salt mixture was later determined to be CaCl2*2H20

(a) write the molecular form of the equation for the reaction.

(b) Write the net ionic equation for the reaction.

(c) How many moles and grams of CaCl2.2H2O reacted in the reaction mixture?

(d) How many moles and grams of excess reactant, K2C2O4.H2O, reacted in the mixture?

(e) How many grams of the K2C2O4.H2O in the salt mixture remain unreacted (in excess)?

(f) What is the precent by mass of each salt in the mixture?

Reference no: EM131893717

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