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Programming in C:
Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal".
#include <stdio.h>#include <math.h>
int main(void) {double targetValue = 0.3333;double sensorReading = 0.0;
sensorReading = 1.0/3.0;
if (/* Your solution goes here */) {printf("Equal\n");}else {printf("Not equal\n");}
return 0;}
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