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A sample of vinegar has a freezing point depression of 2.0 degrees C. What is the estimated percent by mass of acetic acid in the vinegar? Molar mass of acetic acid is 60g/mol
Calculate the molar concentration of OH- ions in a 7.5×10^-2 M solution of ethylamine C2H5NH2(Kb = 6.4x10^-4).
If a reaction mixture contains only N2O and NO2 at partial pressures of 1.0 atm each, the reaction will be spontaneous until some NO forms in the mixture.
Write the overall reaction, showing how much ATP (Adenosine tri phosphate) can be produced per pentose used also write an equation for the generation of NADPH using ribose as a sole source of carbon?
A current of 3.15 A is passed through a Pb(NO3)2 solution for 1.40 hours. How much lead is plated out of the solution.
What is the molarity of a solution prepared by dissolving 10.5 grams of NaF in enough water to produce 750 mL of solution
Identify the nuclide produced when americium-241 decays by alpha emission, 241 / 95 Am→ 4 / 2 He + ? Express your answer as an isotope using prescripts.
Sodium Bisulfite UseThe non-shrinking, non-warping nature of ultramarine blue, along with its exceptional heat and light stability has led to the development of a range of high quality ultramarine blue pigments specifically for masterbatchs applicati..
A 10.00 mL sample of a solution of hydrofluoric acid,HF, is diluted to 500.00 mL. A 20.00 mL sample of the diluted solution requires 13.51 mL of a 0.1500 M NaOH solution to be titrated to the equivalence point.
A sample mixture of CH4 and C2H6 weighing 0.732 g burned to give 2.064 g CO2. What is the mass of CH4 in the mixture.
Find the mass of a reactant using Dalton's law of partial pressures, ideal gas law, and stoichiometry - Determine the amount of zinc metal in grams consumed in the reaction.(Vapor pressure of water at 25 o C-23.8mmHg)
121 cal of heat are added to 50.0 g of water initially at 15.0 (degrees celsius). What is the final temperature of the water.
Estimate the pH at the equivalence point of an HOAc solution if 25.5 mL of this solution required 37.5 mL of 0.175 M NaOH to reach the equivalence point (Ka = 1.8 x 10-5).
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