What is the distance of closest approach of the two particle

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An alpha particle with a kinetic energy of 6.00MeV makes a head-on collision with a gold nucleus at rest.

What is the distance of closest approach of the two particles? (Assume that the gold nucleus remains stationary and that it may be treated as a point charge. The atomic number of gold is 79, and an alpha particle is a helium nucleus consisting of two protons and two neutrons.)

Reference no: EM13277171

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