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In a certain binomial distribution, π = 0.25 and n = 40, In using the normal approximation,
a. What are the mean and standard deviation of the corresponding normal distribution?
b. If the number of "successes" among the 40 observations, determine the following: P(x = 8), P(12 ≤ x ≤16), P(10≤ x ≤12), P(x ≥ 14).
Do these measures of central tendency agree? Explain. What could the measures of dispersion tell us about the results of the quiz?
A confidence interval with a 95% confidence level for the proportion of voters who are in favor of the proposition in a referendum is (0.71, 0.77). How many persons were surveyed in this poll?
Heart disease patients often experience spasms of the coronary arteries. Because biological amines such as serotonin may play a role in these spasms, a research team measured serotonin levels post-mortem from patients who died of heart disease and..
Of all homes having such furnaces, 30% own a type 1 furnace, 25% a type 2 furnace, 15% a type 3, and 30% other types. Over 3 years, 5% of type 1 furnaces, 3% of type 2, 2% of type 3, and 4% of other types have resulted in fires. If a fire occurs i..
hypothesis tests of claims about the population mean or population standard deviation both require a simple random
There is a worker error is 0.3, and the probability that an accident will occur when there is no worker error is 0.2. Find the probability of a worker error if there was an accident.
The results were that 121 people in the sample expressed interest in the plan. Give a 99% confidence interval for the proportion of all interested American Express cardholders.
Auditor wants to be within 7% of true proportion when using 95% confidence level. How many files should auditor sample?
a) What is the probability that 4 or more live in poverty? b) What is the probability that 3 live in poverty? c) What is the expected number (mean) that live in poverty
the one-sample t statistic from a sample of n 15 observations for the two-sided test ofh0 u 64ha u64has the value t
The probability that a standard normal random variable, Z is between 1.00 and 3.00 is
an average american family spends 927 dollars on christmas gifts with standard deviation of 200.what is the probability
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