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A researcher predicts that watching a film on institutionalization will change students' attitudes about chronically mentally ill patients. The researcher randomly selects a class of 36 students, shows them the film, and gives them a questionnaire about their attitudes. The mean score on the questionnaire for these 36 students is 70. The score for a similar class of students who did not see the film is 75. The standard deviation is 12. Using the five steps of hypothesis testing and the 5% significance level (i.e. alpha = .05), does showing the film change students' attitudes towards the chronically mentally ill?
1) What does it mean to set alpha at .05?
2) What is your null hypothesis? Alternate hypothesis?
3) Is this a one-tailed or two-tailed hypothesis?
4) What is your obtained z?
5) What is the critical value of z?
6) Do you reject or fail to reject the null hypothesis? State in words what you have found.
The standard deviation of the sample is 2.5 calls. Using the .05 significance level, can we conclude that the mean number of calls per salesperson per week is more than 44?
The standard deviation was 2. At α = .10, is the number of years' experience of the taxi drivers really less than the taxi company claimed?
Assume X is an exponential random variable with parameter lambda. Find the method of moments estimator for lambda.
The gas price index for 1985 was 218.5 and the gas price index for 2000 was 276.8. If it cost $18.13 to fill your gas tank in 1985, how much would it have cost to fill the same tank in 2000?
The Manager of a seafood restaurant was asked to establish a pricing policy on lobster dinners. Experimenting with prices produced the following data:
Suppose we have the following information from a simple regression: What is the coefficient of determination? What is the correlation coefficient?
The estimated simple linear regression equation minimizes the sum of the squared deviations between each value of Y and the line.
Suppose that past data are not available for developing a planning value for p; therefore, you will use p = 0.050 for the planning average.
Calculate the average or the median of the average or medians of the samples and compare it with the average of the population.
A Private firm reports that 8% of the 2 million small businesses who apply for loan each year receive special interest rate (usually higher than market rate) because of high riskiness associated with small business.
A random sample of 52 groups gave a mean of $8.30 with a standard deviation of $2.42. Find a 90% confidence interval for the mean amount left by all groups.
Does this sample indicate a smaller average? Use α = 0.05 and assume a normally distributed population.
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