This precipitate was removed and the excess hydrazine

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how do you start with the CuSO4 *5H2O, NaOH and N2H6SO4 to get the answer that you just gave at? https://www.chegg.com/homework-help/questions-and-answers/chemical-equation-problem-investigation-reaction-copper-ii-ions-cu2-hydrazine-n2h4-alkalin-q3592517 what would be the chemical equation to this problem? In an investigation of the reaction between copper(II) ions, Cu2+, and hydrazine, N2H4, in alkaline conditions the following observations were made: 25 mL of a solution containing 25 g/L CuSO4.5H2O was mixed with aqueous sodium hydroxide, NaOH. Then 25 mL of a solution containing 13 g/L N2H6SO4 was added. After the evolution of an inert gas had ceased, a fine orange-red precipitate was observed. This precipitate was removed and the excess hydrazine was found to be equivalent to 75 mL of 2.50 X 10-2 mol/L acidified potassium iodate(V), when the following reaction occurred: IO3- + N2H4 + 2 H+ ? N2 + I+ + 3 H2O Deduce the equation for the reaction between copper(II) ions and hydrazine in alkaline conditions. Atomic Masses: Cu = 63.55, S = 32.07, O = 16.00, N = 14.01, H = 1.01

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