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A titration was performed to standardize an EDTA solution. use the following data to calculate the molarity of the EDTA solution. A 50.00 mL aliquot of a standard solution containing 0.025000 M Ca^2+ required 39.92 mL of EDTA to reach a distinct blue endpoint
if 88.6L of H2 measured at STP is allowed to react with 158.3g of P4, what is the limiting reactant?
how much water would they have consumed? How many kJ would be required to bring it to body temperature? (We noted in class that the amount of heat necessary to melt snow is 6.01 kJ/mol)
If you set the freezing point of oleic acid as 0 and the boiling point as 130, what is the freezing point of water on this new scale?
Determine the following characteristics of the titration curve for 25.0 mL of 0.400 M NH3(aq) titrated with 0.335 M HI(aq). (For NH3, Kb = 1.8x10-5.)
In a butane lighter, 9.8 of butane combines with 35.1 of oxygen to form 29.6 carbon dioxide and how many grams of water.
What is the pH of a buffer prepared by adding 0.45 mol of the waek acid HA to 0.608 mol of NaA in 2.00 L of solution? The dissociation constant Ka of HA is 5.66e-7
One liter of 1M acetate buffer at pH = 4.5 is mixed with 600 ml of .5M acetate buffer at pH = 4.8 and then one liter of HCl (0.1M) is added. What is the pH of the final solution?
when 7.50 g of magnesium reacts with 9.50 g hydrochloric acid, hydrogen gas is formed. what is the limiting reagent?
A testing facility found that 8.35*10^23 molecules of carbon dioxide were produced when a sample of octane was burned in air. If this combustion process is known to produce an 86.7% yield, how many grams of octane were in the sample?
calculate the approximate amount of sodium thiosulfate pentahydrate needed to prepare 500mL
Compare the pH vs volume curve for HCL and acetic acid. discuss any difference in the shape of the curves. Compare theese two curves to one of the curves prepared for the unknow
Calculate the electrode potential of the following half cell if it was at standard conditions. Then recalculate how this changes using.
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