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The American Veterinary Medical Association conducted a survey of veterinary clinics to estimate the proportion that do not treat large animals (cows, horses, etc.). The survey was mailed to a random sample of 120 veterinary clinics throughout the country and of these, 88 responded that they do not treat large animals. The standard error SE of the sample proportion p of clinics that do not treat large animals, is
The standard deviation of the sample is 2.5 calls. Using the .05 significance level, can we conclude that the mean number of calls per salesperson per week is more than 44?
If one of the 100 employees is randomly selected, find the probability of getting someone who carpools, someone who cycles to work, or someone who works part time.
question 1. a box has 4 red and 5 blue marbles. as part of an experiment one of the marbles is drawn at random but when
Find the probability that a random sample of 50 customers will take between 90 and 112.5 minutes to complete all their transactions. That is, find the probability that will be between 1.8 and 2.25 minutes.
What the information do z-scores give that actual heights do no?
a sample of 60 women is obtained and their heights in inches and pulse rates in beats per minute are measured. the
Develop a contingency table that shows whether a home has a pool and the township in which the house is located. Is there an association between the variables "pool" and the "township"? Use .05 level of significance.
Standard deviation of 4 beats per minute. If 300 women are examined, how many would you expect to have a heart rate less than 75?
Explain finding value of test statistic and P-value also understand the result. At the .01 significance level can we compute that the mean fare has increased.
The director of Heating and Oil at Mitchell Brothers Company is concerned about the high cost of home heating oil being offered to their customers for the upcoming Fall season in Boston, MA. The company has no possibility of modifying the oil pri..
Construct and interpret 90 percent on confidence interval for the mean. Be sure to interpret the meaning of this interval.
Calculate the sample mean and sample standard deviation.
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