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The enthalpy change for a strong acid-strong base reaction is -56 kJ/mol. Consider a coffee-cup calorimeter in which 0.10 mol of HCl is added to 0.10 mol of NaOH to make 200.0 g of solution. If the initial temperature of the solution is 24.6 deg C and the specific heat capacity of the solution is 4.18 J/g deg C , calculate the final temperature of the reaction mixture.
HCl (aq) + NaOH (aq) ----> H20 (l) + NaCl (aq) dH= -56 kJ/mol
The correct answer is 31.3 deg Celcius. How do you arrive at this answer?
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