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Q1) Researcher would to study the effects of humidity on eating behaviour. It is known that laboratory rats normally eat average of m = 21 grams of food each day. Researcher chooses random sample of n = 16 rats and places in controlled atmosphere room in which relative humidity is maintained at 90%. Daily food consumption scores for rats are as follows:
14, 18, 21, 15, 18, 18, 21, 18, 16, 20, 17, 19, 20, 17, 17, 19
a) Can researcher conclude that humidity has significant effect on eating behaviour? Use two-tailed test with a = 0.05
Assume Nick doesn't know how his received he suppose that all three states of nature are equally likely to occur. If Nick uses the equally likely criterion illustrate what decision would he make.
Findout probabilities utilizing standard normal distribution. If the debt is normally distributed with a standard deviation.
Infer that the difference in the level of satisfaction with service between the two branches.
At.01 significance level, can we conclude that 30-year mortgage rate for small banks is less than 6%? Evaluate the p-value.
Is there evidence that population mean amount is different form 8.17 ounces? (Use a 0.05 level of significance.) with sample standard deviation of 0.051 ounce.
Compute cumulative probabilities for these numbers in second column. Then create a histogram illustrating data distribution. Using generated Normal probability table, determine probability of Pr(X
An experiment was carried out to assess the effects of four tomato varieties and four planting densities on yield. There were 64 plots, and each of the 16 factor combinations was randomly assigned to 4 plots
Determine the z values for 29 and 34 hours. What percent of the garages take between 32 hours and 34 hours to erect?
The trail was repeated 54 times with 22 correct identifications and 32 wrong identification.
If the voice identifications were made by random guess, find the probability that all 9 victims would select the same person?
Constructing a 95% confidence interval for the true length of time for all pepper seeds to germinate you must calculate the margin of error. The margin of error in this case is 0.60.
Find a 95% confidence interval for the mean daily caloric intake. Interpret this interval.
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