Reference no: EM132542450

This question has two parts. First, consider a saturated solution of calcium hydroxide in contact with solid calcium hydroxide:

Ca(OH)2 (s) ⇔ Ca2+ (aq) + 2OH- (aq)

Part 1. If solid NaOH (which is very soluble in water) is added to the solution which is in equilibrium, the concentration of Ca2+ will a. increase b. decrease c. remain unchanged d. cannot be predicted?

Part 2. Which reason or reasons aplly to part 1?

1. This added NaOH is not part of the system and therefore cannot affect equilibrium

2. None of the solid NaOH will dissolve so the number of collisions between particles will not change

3. Adding a solid has no effect on equilibrium

4. More Ca(OH)2 will be produced in order to counter the increase in concentration of OH-

5. A new substance is added resulting in a new equilibrium

6. There will be more collisions between ions of Ca2+ (aq) and OH- (aq) resulting in the formation of more Ca(OH)2

7. The ratio of concentration of products compared to reactants as expressed by Q increases so it is greater than K, and more Ca(OH)2 will be formed

11) Consider the following reaction at equilibrium. If you remove SO3, what happens to the system?

SO2(g) + NO2(g) ? SO3(g) + NO(g)

What happens to the partial pressure of SO2, NO2, SO3, and NO? increases or decreses?

12) According to Collision Theory, reactant molecules are constantly colliding with each other, but only occasionally reacting. What two conditions must be met for a collision to result in a reaction?

13) Is the activation energy for a forward reaction the same as the activation energy for the reverse of the same reaction? Explain your answer by providing a sketch of a reaction energy diagram, in which you label the activation energy.