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Difference in the level of satisfaction with service between the two branches:
A bank is comparing the quality of service given by its two most important branches. In branch A, 192 out of a random selection of 300 of its customers said that they were satisfied with the service. In branch B, 138 out of 250 randomly selected customers said that they were satisfied with the service.
Estimate with 90% confidence the difference in the level of satisfaction with service between the two branches.
Calculate chi-square for the cross-tab. Show your work. Is there a statistically significant relationship between these variables?
Findout the margin of error for this survey if we want a 99 percent confidence in our estimate of the percent of adults over 50 who take vitamin supplements.
Perform a hypothesis test with significance level 5%. Show all work, and clearly state your conclusion.
Find the probability that 4 of the 5 committee members belong to a union.Find the probability using hypergeometric distribution.
In what height interval must the company expect to determine middle 70% of kindergarteners?
The hypothesis that the samples came from identical populations cannot be rejected, the T value is 16.5 greater that the lower limit.
Suppose population standard deviation for those drinking regular coffee is 1.20 cups per day and 1.36 cups per day for those drinking decaffeinated coffee.
Describe why the normal distribution can be used as an approximation to binomial distribution. What conditions should be met to use the normal distribution to approximate the binomial distribution? Why is a correction for continuity essential.
Election poll reported that applicant had n approval rating 31% with margin of error E of 4%. Create a confidence interval for proportion of adults who approved of applicant.
Assume the arrival of these emails i3 approximated by the Poisson distribution.
A Correlation matrix (correlation, coefficients and probability level under the hypothesis rho = 0) for a company's sales force (age, years of service, and current sales) is given below. Comment.
Utlizing binomial approximation to normal finding the normal model. A grower claims that only 13 percent of the strawberries he grows are unsatisfactory.
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