Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
a. A lumber company has just taken delivery on a lot of 10,000 2 x 4 boards. Suppose that 20% of these boards (2000) are actually too green to be used in rst-quality construction. Two boards are selected at random, one after the other. Let A = {the rst board is green} and B = {the sec- ond board is green}. Compute P(A), P(B), and P(A n B) (a tree diagram might help). Are A and B independent?
b. With A and B independent and P(A) = P(B) = .2, what is P(A n B)? How much difference is there between this answer and P(A n B) in part (a)? For purposes of calculating P(A n B), can we as- sume that A and B of part (a) are independent to obtain essentially the correct probability?
c. Suppose the lot consists of ten boards, of which two are green. Does the assumption of independence now yield approximately the cor- rect answer for P(A n B)? What is the critical difference between the situation here and that of part (a)? When do you think that an indepen- dence assumption would be valid in obtaining an approximately correct answer to P(A n B)?
The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample mean of 14.44 with a standard deviation of 4.45 pages. (a) At the .01 level of significance, is the true mean greater than 10? (b) Use Excel to find the..
How many commercials' worth of data do I need to have a margin of error no more than 3, the correct set of hypotheses
The standard deviation of the sample was 1.7 years. Using the 0.95 degree of confidence, what is the confidence interval within which the population mean lies?
Test hypothesis that annual incomes of corporate trainers in areas of more than 500,000 are considerably more than those in areas of less than 100,000. Make use of the 5% level of risk.
Find a 95% confidence interval for the mean dielectric strength of the oil.
The foreman at a large plant estimates defective parts about 1.5% of the time. If the plant produces 25,000 parts in a week, what is the standard deviation (to the nearest tenth) for the number of defective parts?
If a sample of 20 dish owners is randomly selected the what would be the probability that more than 11 dish owners in the sample subscribe to at least one premium movie channel?
Nicotine in cigarettes. To determine whether the mean nicotine content of a brand of cigarettes is greater than the advertised value of 1.4 milligrams, a health advocacy group tests
To determine whether or not they have a certain desease, 80 people are to have their blood tested. However, rather than testing each individual separately, it has been decided first to group the people in groups of 10.
Assuming everyone I ask says East, how does the probability change with the sample size? In other words, how is the probability different if 50 out 50 women say East instead of 5 out of 5 women?
Use formula z=(mean of values in sample - mu subscript mean of values in sample) divided by (lower case sigma divided by sqrt number of values in sample)
By taking the Laplace transform and using the convolution theorem, obtain the solution of the integral equation f(t) = 1+t+int[(t-u)f(u)du,u=0..t)
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +1-415-670-9521
Phone: +1-415-670-9521
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd