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Suppose that 25% of US males and 23% of US females never eat breakfast. Suppose a random sample of 250 men and 250 women is taken and polled about eating breakfast.
a) What is the probabilty that at least 110 of these 500 people never eat breakfast?
b) What is the probability that the number of women who never eat breakfast is at least as large as the number of men who never eat breakfast?
At the .01 significance level, can the manufacturer conclude that the price reduction resulted in an increase in sales?
Assuming the standard deviation stays the same, how much do you have to reduce your average production time so that 95% of the time you can deliver the product in under 75 hours?
If the z score is less than 0, what can be said of the corresponding raw score?
1. suppose a realtor is interested in comparing the asking prices of homes in philadelphia and baltimore. a random
A researcher administers a treatment to a sample of n = 25 participants and uses a hypothesis test to evaluate the effect of the treatment.
The carpeting department supervisor claims that the average number of days between the receipt of a complaint and its resolution is 20 days or less.
An opinion poll was taken to see how people felt about Health Care reform. Previous poll results indicate that within a particular population 34% were for reform, 41% were against reform, and 25% were uncertain.
Produced weigh between 100 grams up to the mean and 49.18% weigh from the mean up to 190 grams. Determine the mean and the standard deviation.
a sample of 25 patients in a doctors office showed that they had to wait an average of 35 minutes with a standard
When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions.
1. Suppose you are given a particular set of data and found that r = 2.5. How would you interpret this result?
An internal study by the Technology Services department at Lahey Electronics revealed company employees receive an average of 6.0 emails per hour. Assume the arrival of these emails is approximated by the Poisson distribution.
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