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In the following situation, assume the random variable is normally distributed and use a normal distribution or a t-distribution to construct a 90% confidence interval for the population mean. If convenient, use technology to construct the confidence interval.
(a) In a random sample of 10 adults from a nearby county, the mean waste generated per person per day was 4.35 pounds and the standard deviation was 1.88 pounds.
(b) Repeat part (a), assuming the same statistics came from a sample size of 500. Compare the results.
(a) For the sample of 10 adults, the 90% confidence interval is ( ), ( ). Round to two decimal places as needed.
(b)Now assume the sample came from a sample size of 500. Compare the results.
Determine whether the description corresponds to an observational study or an experiment. Thirty university students are divided into two groups, one group receives free tutoring in mathematics, the other does not.
Perform a proper analysis. Describe your null and alternative hypothesis, report the p-value. What is your conclusion?
A psychology professor is interested in whether implementing weekly quizzes improves student learning. She decides to use the weekly quizzes in one section of her introductory psychology class and not to use them in another section of the same cou..
A researcher wishes to estimate with 99% confidence, the proportion of adults who have high-speed Internet access. Her estimate must be accurate within 2% of the true proportion.
For a new HDTV the mean number of months until repairs are needed is 36.84 with a standard deviation of 3.34 months.
Create the indicated confidence interval for population mean µ using a t- distribution.
Using ANOVA summary table, find out if regression model is significant.
Does the data prove a significant difference in mean times?
Then describe trade-offs which will happen when you lower sample to $10,000 to meet their budget.
Pproportion who are sent to prison after pleading innocent and being found guilty? No, as the test value -1.96 is inside interval (-2.58, 2.58), No, as the test value -4.94 is outside interval (-1.96, 1.96).
Calculate a value of lambda using the data from last week concerning the news networks and the reporting practices. Compare your resulting lambda to the resulting chi-square from last week.
Two groups of students are asked to rank their preference for six types of soft drinks. The following table shows their rankings.
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