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A random sample of 10 observations from one population revealed a sample mean of 23 and a sample deviation of 4. A random sample of 8 observations from another population revealed a sample mean of 26 and a sample standard deviation of 5. At the .05 significance level, is there a difference between the population means.
(a) Compute the pooled estimate of the population variance.
(b) Compute the test statistic.
(c) State the decision about the null hypothesis.
(d) Estimate the p-value.
Note that under the exponential assumption, P(X>t) = exp(-t/theta). If t=5, use the result from (a) to find an approximate one-sided lower 95% confidence limit for theta.
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