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In an October 2012 survey of 7,786 randomly selected adults living in Germany, 5,840 said they exercised for at least 30 minutes three or more times per week.
If an exercise scientist wants to estimate the proportion of American adults who exercise for 30 minutes three or more times per week. He wants to construct a 90% confidence interval with a margin of error of 1%. Note that Americans are typically thought to not be as active as individuals in other co untries, and thus the estimate from Germany is likely not a good estimate for Americans. What sample size does he need?
Use the binomial distribution in the Data Analysis add - in to simulate the distribution of men and women among the next ten arrivals at an emergency room, assuming that, on average, six people out of ten who arrive are men.
In a study of the lizard Sceloporis occidentalis, researchers examined field-caught lizards for infection by the malarial parasite Plasmodium. To help assess the ecological impact of malarial infection, researchers tested 15 infected and 15 noninf..
why the rise in performance on IQ tests contrasts with a steady decline in performance over the past decades on many standardized tests,
What is the possible uses of regression and correlation analysis in doctoral-level research? Would I be able to use these techniques in my dissertation, or any application in other areas?
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Find the z-scores that bound the middle 15% of the standard normal distribution. (Give your answers correct to two decimal places.
He would like 95% confidence intervals for the average price people would be willing to pay: one for the higher-income group, one for the lower-income group.
Using what you know about t-scores, identify which of the variables have a significant influence on the LISTPRICE. At a level of 1% which variables are significant?
consider a carton of twelve eggs of which three are rotten. suppose we randomly select five eggs. compute the
The top motivation is for using a credit card. Can you conclude that there has been a chagne in the claimed or expected distribution? Use a =0.025.
At the .01 level of signiicance, is the true mean greater than 10?
The counts in the five groups are 113, 95, 108, 99, and 85, respectively. The probabilities for these five intervals are all the same. What is this probability?
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