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Someone claims that the mean age of residents of a certain neighborhood is 50, but you suspect that the mean age is actually higher than that. A sample of 36 residents reveals a mean age of 53, with a sample standard deviation of 15.
a. State the null and alternative hypotheses.
b. Compute the value of the test statistic.
c. Taking α to be 0.05, what is/are the critical values associated with testing your hypothesis?
d. What conclusion do you come to?
Complete the ANOVA table. Carry out a test of hypothesis on each of regression coefficients. Could you delete any of the variables?
The number of standard errors that the sample estimate (p 1 - p 2 ) of (p1 - p2) falls from its null hypothesis value of zero is called
According to Advertising Age, average base salary for women working as copywriters in advertising firms is higher than average base salary for men. The average base salary for women is $67,000 and the average base salary for men is $65,500 (Workin..
A random sample of 100 students at Southern University was collected. The mean age was found to be 24.2 years, with a standard deviation of 3.4 years.
Determine the mean number of times the machine was used per day.
How much do typical employee and his or her family spends per year on dental expenses? Sample of 45 employee reveals mean amount spend last year was $1,820, with standard deviation of $ 660.
How large random sample of potential voters will be required to evaluate result with 95% confidence and with margin of error of plus and minus 3%?
Compute the probability that student eats at fast food restaurant 2 or more times per week?
The random variable xi represents the number of complaints, and p(xi) is the probability of receiving xi complaints.
compute the expected value and variance of U.Determine Expected value and variance using uniform distribution.
Compute the correlation among the variables. Describe perfect correlation also negative correlation. Utilize the following data to answer questions related.
I want to establish if a new product is worth marketing. At least 85 percent of the public must express interest in the product and for those that do the average cost they are willing to pay must be at least $47.50.
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