Reference no: EM13161162

d named hasAnOddDigit that returns whether any digit of a positive integer is odd. Your method should return true if the number has at least one odd digit and false if none of its digits are odd. 0, 2, 4, 6, and 8 are even digits, and 1, 3, 5, 7, 9 are odd digits.

For example, here are some calls to your method and their expected results:

Call	Value Returned
hasAnOddDigit(4822116)	true
hasAnOddDigit(2448)	false
hasAnOddDigit(-7004)	true

You should not use a String to solve this problem.

my code:

public boolean hasAnOddDigit(int num){
// You do not need to make a copy of num, because
// of pass-by-value semantic: since num is a copy,
// you can change it inside the method as you see fit.
while (num > 0) {
int digit = num % 10;
if (digit % 2 == 1) return true;
num /= 10;
}
// If we made it through the loop without hitting an odd digit,
// all digits must be even
return false;
}

error:

#	name	expected return	your return	result
1	hasAnOddDigit(4822116)	true	true	pass
2	hasAnOddDigit(2448)	false	false	pass
3	hasAnOddDigit(8910437)	true	true	pass
4	hasAnOddDigit(6022048)	false	false	pass
5	hasAnOddDigit(824876248)	true	true	pass
6	hasAnOddDigit(1375335)	true	true	pass
7	hasAnOddDigit(42)	false	false	pass
8	hasAnOddDigit(70)	true	true	pass
9	hasAnOddDigit(4)	false	false	pass
10	hasAnOddDigit(3)	true	true	pass
11	hasAnOddDigit(0)	false	false	pass
12	hasAnOddDigit(-7004)	true	false	fail
13	hasAnOddDigit(-24806)	false	false	pass