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An experiment was conducted to compare the weights of the combs of roosters fed two different vitamin-supplemented diets. Twenty-eight healthy roosters were randomly divided into two groups, with one group receiving diet I and the other receiving diet II. After the study period the comb weight (in milligrams) was recorded for each rooster. The data are:
DietI
73 130 115 144 127 126 112 76
68 101 126 49 110 123
DietII
80 72 73 60 55 74 67 89
75 66 93 75 68 76
a)
Suppose you wanted to conduct a nonparametric test to compare these data. Using
α = .05, complete the following:
H0:
Ha: (two-sided):
Value of test statistic:
p-value:
Conclusion:
b) Suppose the experimenters submitted a scientific paper on their results, and received a number of suggestions from referees. One referee suggests that the underlying distributions are normally distributed, and hence that one should compare the two mean weights. Suppose you investigate comparing means assuming normality. Give the formula for the proper statistic to use, and also the p-value.
Formula for test statistic:
p-value::
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Use simple exponential smoothing with α = 0.33 to forecast battery sales for February through May. Assume that the forecast for January was for 22 set of tires.
A survey on the drinking habits of Americans estimated the percentage of adults across the country who drink beer, wine, or hard liquor at least occasionally. Of the 1516 adults interviewed, 985 said that they drank.
Find the percent of a standard Normal model found in the given region. Round to the nearest hundredth of a percent.
BMI in children is approximately normally distributed with a mean of 24.5 and a standard deviation of 6.2. A BMI between 25 and 30 is considered overweight. What proportions of children are overweight?
If the sample proportion is .45, and the standard error of the sample proportion is .035, the appropriate conclusion would be to reject 0 H?
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Sampling variability refers to the idea that different samples will include different individuals
Construct the 90% and 95% interval estimates for the population mean weekly sales.
If new inspector measures 101 stampings with variance of 0.13 square inch, test at 0.05 level of significance whether inspector is making satisfactory measurements. Suppose normality.
Describe your answer to a person who has never had a course in statistics.
How would figure out a 90% and 95% confidence interval for the below informaion? What would be the formula? Can I figure this out in Excel or Megastat? How would I do that?
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