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The solubility product of PbBr2 is 8.9x10^-6. Determine the molar solubility a) in pure water, b) in 0.20M KBr solution, c) in 0.20M Pb(NO3)2 solution.
115 mL of H_2O is initially at room temperature 22 0C. A chilled steel rod at 2 0C is placed in the water. If the final temperature of the system is 21.1 0C, what is the mass of the steel bar.
another part says spectra of caffeine, benzoic acid, and a mountain dew sample in 0.10 M HCl. On a graph it has the points 8.74 mg/L for benzoic acid, 1.5 dilution for mountain dew soda,
What is the pH of a solution prepared by mixing 100 mL of 0.020 M Ca(OH)2 with 50 mL of 0.100 M NaOH? assume that the volumes are additive.
The compounds below cannot be identifed from IR and H NMR spectra alone. Explain. Suggest how other types of spectroscopy might be useful in solving the structure
The resulting solution required 51.30 mL of 0.08765 M AgNO3(aq) to precipitate the Cl-(aq) and Br-(aq) as AgCl(s) and AgBr(s). Calculate the mass percentage of NaCl(s) in the mixture.
Both CsCl and CaF2 exhibit a coordination number of 8 for the cations. What is the structural relationship between these two lattices
If you dilute 750.00 mL of a 4.117 × 10-4 M solution into a 2.00 L volumetric flask and fill to the line with water, what would be the final concentration of the solution?
Calculate the energy that must be removed to convert substance X from a gas at 119°C to a solid -47.9°C.
Explain why it is preferable to take the geometric mean rather than the arithmetic mean when defining mean activity
Which weak acid would be best to use when preparing a buffer solution with a pH of 9.70? An acid with Ka = 3.2 × 10^-5 An acid with Ka = 4.0 × 10^-7 An acid with Ka = 1.3 × 10^-11 An acid with Ka = 2.1 × 10^-10
Why do we have to turn the solution very acidic first before we convert the ions into sulfides? Why don't we just make the sulfides first with the unknown?
what is the standad potential for I 2 being reduced to I- given that the standard reduction potential for Cr2O7 2- changing to Cr3+ is +1.33V I got to
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