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Find 95 percent confidence interval for population mean:
A college student is doing some research on the cost of one-bedroom apartments in town. He has randomly selected 25 apartments for which the price was published. The average price for these apartments is = $652. He will assume that price follows roughly a normal distribution. Based on prices from previous years, a real estate agent gives him the information that σ is approximately $55. A 95% confidence interval for µ is found to be 652 ± 21.56 = ($630.44, $673.56). Determine which of the following statements is true.
A) A test of the hypotheses H0: µ0 = 650 vs. Ha: µ1 < 650 would be rejected at the 0.05 level.
B) A test of the hypotheses H0: µ0 = 650 vs. Ha: µ1 > 650 would be rejected at the 0.05 level.
C) A test of the hypotheses H0: µ0 = 675 vs. Ha: µ1 ≠ 675 would be rejected at the 0.05 level.
D) All the above.
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Construct a 90 percent confidence interval for the proportion of all kernels that would not pop.
Last school year, student body of a local university consisted of 30% freshmen, 24% sophomores, 26% juniors, and 20% seniors. A sample of 300 students taken from this year's student body showed the following number of students in each classificati..
A sample of twenty automobiles was taken, and the miles per gallon (MPG), horsepower, and total weight were recorded. Develop a linear regression model to predict MPG using horsepower as the only independent variable. Develop another model with weig..
Determine mean and standard deviation for number of erroneous returns per batch.
At.02 significance level is it sensible to conclude that mean number of shoes sold at mall stores is larger than at outlet stores?
Suppose the weights of full boxes of a certain kind of cereal are normally distributed with a population standard deviation of 0.29 ounces.
Which of the following is the appropriate conclusion from carrying out these multiple comparisons
Difference in the mean number of times men and women order take-out dinners in a month? What is the p-value?
At the 5% significance level, if the sample proportion is .45, and the standard error of the sample proportion is .035, the appropriate conclusion would be:
a. Solve using the p value approch. b. Solve using the classical approch.
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