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Explain why we use the term do not reject h0 and not accept

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Reference no: EM13578566

Part (a)

Suppose that someone claims that adult koalas eat an average of 392 grams of eucalyptus leaves per day. Using information from a sample of 50 koalas (sample mean = 395 grams, sample standard deviation = 53 grams), carry out a hypothesis test (via the 6-step procedure or using the p-value) with a level of significance a = 0.01 to test H0: µ = 392 and show your work.

Part (b)

Does your result in part (a) prove that the population mean is 392 grams? Explain your answer.

Part (c)

Suppose that someone claims that adult koalas eat an average of 398 grams of eucalyptus leaves per day. Using information from a sample of 50 koalas (sample mean = 395 grams, sample standard deviation = 53 grams), carry out a hypothesis test (via the 6-step procedure or using the p-value) with a level of significance a = 0.01 to test H0: µ = 398 and show your work.

Part (d)

Does your result in part (c) prove that the population mean is 398 grams? Explain your answer.

Part (e)

Use your results from above, to explain why we use the term "do not reject H0" and not "accept H0". (Hint: You may also wish to go back to your answers to parts (b) and (d) to make sure that they are consistent with your answer to this part.)

Reference no: EM13578566

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