Explain what will be the initial rate

Reference no: EM13336243

For the following reaction: ?NH?_4^+(aq) + ?NO?_2^-(aq) ? N2(g) + 2H2O(l) the rate law is: rate = k[?NH?_4^+ ] [?NO?_2^- ]^2 for an experiment, the initial rate is 0.03 mol L-1 s-1 when the initial concentrations are: [?NH?_4^+ ]_0 = 0.015 mol L-1 and [?NO?_2^- ]_0 = 0.02 mol L-1. What will be the initial rate (in mol L-1 s-1) when the initial concentrations are: [?NH?_4^+ ]_0 = 0.03 mol L-1 and [?NO?_2^- ]_0 = 0.04 mol L-1? A) 0.06 B) 0.12 C) 0.18 D) 0.24

Reference no: EM13336243

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