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What temperature would have to be maintained to have 1.4 moles of CO2, at 78 kPa, occupy a volume of 22.4 L?
a. 0.0067 Kb. 273 Kc. 150 Kd. none of the above
how do i prepare 50 mL of the 0.00625 M HCl solution by an appropriate dilution of the 0.0125 M HCl solution
a solution is initially 2.5 ? 10-3 m in cu and 2.5 ? 10-3 in pb 2. iodine ion is gradually added to the solution.
What is the approximate pH of a solution of the salt NH4(O2CCH3) (ammonium acetate)? No calculations -- only reasoning needed. pKa/pKb values in your notes
The following reaction is endothermic in the forward direction. NH4Cl(s) NH3(g) + HCl(g) For each of the following cases, briefly explain whether the action causes net reaction from left to right, right to left, or no net reaction.
Designate True (T) or False (F) for each of the following statements and a sample of an optically active substance that consists of a single enantiomer is said to have an enantiomeric excess of 100%.
The heat of formation of liquid diatomic bromine is 0 kJ/mole. The heat of formation of gaseous diatomic bromine 30.9 kJ/mole. The heat of formation of gaseous monatomic bromine
A 1.00 g sample of an unknown acid required 17.0 mL of .650 M NaOH to neutralize. What is the molar mass of the unknown acid?
Calculate the pH of a solution containing 25.00 mL of 0.12 M formic acid (Ka = 1.7 x 10^-4) to which the following amounts of 0.10 M NaOH have been added
Calculate the systematic treatment of equilibrium. Remember C2O4^2- is a weak base so you must consider other equilibria. (Ksp(ZnC2O4)=7.5X10^-9, Kb1=1.8X10^-10, Kb2=1.8X10^-13). Solve using systematic treatment of equilibrium.
What is the name of the chemical used in Sweet 'n Low? Draw the structure. Why was a temporary restriction placed on the use of this sweetener? What is the Delaney Amendment?
Why is it possible to separate the product (6-ethoxycarbonyl-3,5-diphenyl-2-cyclohexenone) from sodium hydroxide using acetone?
Draw complete lewis structure of condensed structural formula. (CH3)3(3 is a subscript)CCOCHCH2
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