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Explain what is the volume in ml of 0.185 m hcl

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What is the volume in mL of 0.185 M HCl(aq) needed to reach halfway to the equivalence (stoichiometric) point in the titration of 47.0 mL of 0.196 M N2H4(aq) (Kb = 1.7 x 10^-6).

Reference no: EM13325773

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