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we use 1 g of unknown acid added with 120 mL of distilled water ,the solution filtered , then we took 25 mL of this unknown acid for titration.we use NaOH base for titration ,the volum of titrated base when it reach the equivalence point was 3.2 mL . and the concentration of NaOH is 0.1 M.
I calculate the numbers of moles of NaOH = 0.0003233 mol
Q: What is the initial concentration of unknown acid?
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