Explain to convert this into a buffer having a ph

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You have 4.507 L of a 0.1572 M H3BO3 (boric acid, Ka = 5.800x10-10) solution. To convert this into a buffer having a pH of 9.3380, how many grams of KH2BO3 (M.W. 99.926) should be added to the solution?

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