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Propranolol is an adrenergic antagonist. Compare the structure of propranolol with noradrenaline and identify which features are similar in both molecules. Suggest why this molecule might act as an antagonist rather than an agonist, and whether it might show any selectivity between the different types of adrenergic receptor.
A mass of 57 g of lead fishing weight absorbs heat of 146 Calories. Determine its final temperature If its initial temperature =48 Centigrade,?
Which absorption band is more intense; a band due to a single S-O bond or a band due to a single Si-C bond? 2) Compound A (C21H32) decolorizes a solution of bromine in CCl4
A 31.43 ml volume of .108M NaOH is require to reach the phenolphthalein endpoint in the titration of a 4.441g sample of vinegar. Calcute the percent acetic acid in the vinegar.
A sample of lead releases 221 kJ of heat when freezing. What is the mass of the sample? DHfus = 23 J/g
an activation energy of 43.6 kJ/mol, what will be the rate constant for this reaction at 75oC?
a 0.5224-g sample of an unknown monoprotic acid was titrated with 0.0998M of NaOH. the equivalence point of the titration occurs at 23.82ml. Determine the molar mass of the unknown acid
What mass of HCl gas must be added to 1.00 L of a buffer solution that contains [acetic acid] = 2.0 M and [acetate] = 1.0 M in order to produce a solution
A 120g sample of an unknown substance was heated from 15oC to 30oC. The substance absorbed 458 joules of energy. What is the specific heat of this substance?
Determine ΔHreaction° for: 4H2O (l) + 2 NH3 (g) → 2NO2 (g) + 7H2 (g) using the following two equations: (1) N2 (g) + 3H2 (g) → 2 NH3 (g) ΔH1° = -184 kJ (2) 4NO2 (g) + 8H2 (g) → 2 N2 (g) + 8 H2O (l) ΔH2° = -196 kJ
If 2.45 g of N2H4 reacts and produces 0.650 L of N2, at 295 K and 1.00 atm, what is the percent yield of the reaction?
Electrons are ejected from sodium metal by any light that has a wavelength shorter than 544 nm. What is the kinetic energy of an electron
Calculate the mass of KI in grams required to prepare 4.00 102 mL of a 2.80 M solution.
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