Explain the reaction if the partial pressures

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a) Calculate ?Go and Kp for the following equibibrium reaction at 25'C/ The ?Gf o values are 0 for Cl2(g), -286 kJ/mol for PCl3(g), and -325 kJ/mol for PCl5(g). b) calculate ?G for the reaction if the partial pressures of the initial mixture are PPCl5 = 0.0029 atm, PPCl3 = 0.27 atm, and PCl2 = 0.40 atm ( Kp = e^-?Go/RT where R = 8.314 J/K mol. Hint part B: Find the Qp) PCl5(g) <---> PCl3(g) + Cl2(g)

Reference no: EM13491459

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