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Problem- Sulfur trioxide, SO3, is made from the oxidation of SO2, and the reaction is represented by the equation: 2SO2 + O2 -->® 2SO3 A 21-g sample of SO2 gives 18 g of SO3. The percent yield of SO3 is.
Anyone can tell me how to solve it step by step so that I will be able to understand what is going on?
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