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Given the heat of combustion for the following reactions, determine the enthalpy of formation for pentane, C5H12.
C5H12 (l) + 8O2 (g) ----> 5CO2 (g) + 6H2O (l)Delta H = -3505.8 kJ/mol
C (s) + O2 (g) -----> CO2 (g)Delta H = -393.5 kJ/mol
H2 (g) + (1/2)O2 (g) ------> H2O (l)Delta H = -286 kJ/mol
Possible answers:
a. +35 kJ/mol
b. + 1,073 kJ/mol
c. -4,185 kJ/mol
d. -2,826 kJ/mol
e. -178 kJ/mol
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