Explain the following reversible reaction

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Consider the following reversible reaction. In a 1-liter container the following amounts are found in euilibrium at 400 deg C., 0.0536 mole N2, 0.599 mole H2, and 0.0437 mole NH3. Evaluate Kc = N2(g) + 3 H2(g)-> 2 NH3(g) answer in significant figures Pleae show work so I can have a better idea of solving

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