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listening to music mat be relaxing or it may be distracting. to determine which , 49 participants are tested while listening to music and they produced a mean of 54.63. the mean of the population of students who have taken the test without music is 50. (a) should we use a one tailed or a two tailed test ? why? (b) what are our h0 and ha ? (c) compute zobt.(d) with a= .05, what is zcrit? (E) do we have evidence of a relationship in the population? if so describe the relationship.
Develop a 99% confidence interval for the population proportion.
The National Center for Education Statistics reported that 47% of college students work to pay for tuition and living expenses. Assume that a sample of 450 college students was used in the study.
Test the teachers hypothesis that there is a significant difference between the pre and post tests.
A manufacturer of automobile transmissions uses three different processes. The management ordered a study of the production costs to see if there is a difference among the three processes. A summary of the findings is shown below.
The hypothesis is to be tested at the 5% level of significance. The critical value from the table equals:
Assume you always reject null hypothesis, regardless of any sample evidence. Determine the probabiliyt of Type II error? P(Type II error).
What is the degree of correlation between the dependent variable and the independent variable? Is the statistical significance of the model as a whole less than the desired statistical significance for the regression model? Explain the basis for yo..
Based on its 1999 survey, Student Monitor reports that 20% of U.S. college students used the Internet for job hunting during the month preceding the survey.
Fair die is rolled 10 times. Determine the probability that the odd number (1, 3 or 5) will occur less than 4 times?
Estimating the combined mean values for the given data - find the mean for the combined sample
Produce the scatter plot for sodium and bp. Do you think there are any outliers?
The population of SAT scores forms a normal distribution with a mean of µ=500 and a standard deviation of o =100. If the average SAT score is calculated for a sample of n=25 students,
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