Explain a volume of 90.0ml of aqueous potassium hydroxide

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Reference no: EM13565524

A volume of 90.0mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the KOH solution if 20.2 mL of 1.50M H2SO4 was needed? The equation is:

2KOH(aq) + H2SO4(aq) ---> K2SO4(aq) + 2H2O(l)

Reference no: EM13565524

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